Question

Find three consecutive number whole number whose sum is more than 45 but less than 54.

Answer 1

Answer:

15 , 16,17

Step-by-step explanation:

15+16+17=48

Answer 2

Let the numbers be a-1, a, a+1

Their sum is a-1+a+a+1 = 3a = X

From given conditions,

45<X<54

45<3a<54

15<a<18

Hence the value of a could be 16 or 17.

Thus the numbers could be 15,16,17 or 16,17,18.

But verifying them using given conditions i.e., their sums should be 48

For by verifying it can be concluded that the numbers are surely 15,16,17.