Question

find three consecutive number whose sum is 108

Answer 1

Hola

$\sf\huge{Answer}$

Let the three consecutive numbers be

x, x + 1, x + 2

Their sum = 108

Therefore we get an equation -

x + x + 1 + x + 2 = 108

3x + 3 = 108

3x = 108 - 3

3x = 105

x = 105/3

=> 35

Therefore the value of x = 35

Thus, the three consecutive numbers =

x = 35, x + 1 = 35 + 1 = 36, x + 2 = 35 + 2 = 37

$\bf{Three\:numbers\:are\:35\:36\:37\:}$

Hope it helps!

Answer 2

x+x+1+x+2=108
3x+3=108
3x=108-3
3x=105
X=105/3
X=35
Numbers are 35,36,37