find three consecutive number whose sum is 147
Answers
Answered by
0
Answer:
48, 49 and 50.
Step-by-step explanation:
Let the numbers are a - 1 , a and a + 1.
As their sum is 147
⇒ ( a - 1 ) + a + ( a + 1 ) = 147
⇒ a - 1 + a + a + 1 = 147
⇒ a + a + a = 147
⇒ 3a = 147
⇒ a = 147 / 3
⇒ a = 49
Hence the numbers are 49 - 1 = 48 ; 49 and 49 + 1 = 50
Answered by
0
Answer:
Step-by-step explanation:
Let the no =x
x+x+1+x+2=147
3x+3=147
3x=147-3
3x=144
x=144/3
x=47
The first number =47
The second number = 48
The third number =49
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