Question

find three consecutive numbers such as that the sum of the second and the third number exceed the first by 14

Answer 1

Answer:

11, 12, 13

Step-by-step explanation:

Let the first number be x

the second and third numbers are x + 1 and x + 2

The three consecutive numbers are x, x + 1, x + 2

Sum of the second and the third number exceed the first by 14 =

(x + 1) + (x + 2) - x = 14

=> 2x + 3 - x = 14

=> x + 3 = 14

=> x = 11

The 3 numbers are 11, 12, 13