Question

find three consecutive numbers such that if they are divided by 10 17 26 respectively the sum of their quotients will be10​

Answer 1

Let the consecutive no.s be x, x+1, x+2
According to the question,
x/10+ (x+1)/17 + (x+2)/26 = 10
So, we take lcm and add,
We get
(221x + 130x + 130 + 85x+ 170)/2210= 10
So, by cross multiplying
436x + 300 = 22100
436x = 21800
X= 21800/436
x= 50
So the no.s are 50, 51, 52

Answer 2

Answer:

Step-by-step explanation:

Let the consecutive no.s be x, x+1, x+2

According to the question,

x/10+ (x+1)/17 + (x+2)/26 = 10

So, we take lcm and add,

We get

(221x + 130x + 130 + 85x+ 170)/2210= 10

So, by cross multiplying

436x + 300 = 22100

436x = 21800

X= 21800/436

x= 50

So the no.s are 50, 51, 52