Question

Find three consecutive numbers such that if they are divided by 10, 17, and 26 respectively,
the sum of their quotients will be 10.
(Hint: Let the consecutive numbers = x , x + 1,x+2, then
x. x + x + 2
+
+
10 17 26
= 10)​

Answer 1

Answer:

Let X, (X+1), (X+2) are 3

consecutive numbers.X/10 +

(X+1)/17+ (X+2)/26 =10L.C.M

= 4420(442(X) +260(X+1)

+170(X+2))/

4420=10(442x+260x+260+

70x+340)=

4420×10(442x+260x+170x+2

60+340)=44200872x + 600=

44200872x= 44200-

600872x= 43600X=

43600/872X= 50

Ist no. (X)= 50

Ist no. (X)= 502nd no.(x+1)=

50+1= 51

Ist no. (X)= 502nd no.(x+1)=

50+1= 513rd no.(x+2)=

50+2=52

The 3 consecutive numbers are 50, 51, 52

Hope this will help you...

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