find three consecutive numbers such that if they are divided by 10, 17 and 26 respectively , the sum of their quotient will be 10
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Step-by-step explanation:
Let the consecutive numbers be x,x+1 and x+2
If they are divided by 10,17 and 26 respectively,
Then,
10
x
+
17
x+1
+
26
x+2
=10
⇒442x+(260)(x+1)+(170)(x+2)=442×100
⇒872x+600=442×100
⇒x=50
So, the consecutive numbers are 50,51 and 52
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