Question

Find three consecutive numbers such that if they are divided by 10, 17, and 26 respectively, the sum of their quotients will be 10.
(Hint: Let the consecutive numbers = x , x + 1, x + 2 , then x/10 + (x+1)/17 +(x+2)/26 =10
answer should come 127/12​

Answer 1

Answer:

Let X, (X+1), (X+2) are 3 consecutive numbers.

X/10 + (X+1)/17+ (X+2)/26 =10

L.C.M = 4420

(442(X) +260(X+1) +170(X+2))/4420=10

(442x+260x+260+170x+340)= 4420×10

(442x+260x+170x+260+340)=44200

872x + 600= 44200

872x= 44200- 600

872x= 43600

X= 43600/872

X= 50

_____________________________

Ist no. (X)= 50

2nd no.(x+1)= 50+1= 51

3rd no.(x+2)= 50+2= 52

____________________________

The 3 consecutive numbers are 50, 51, 52

_____________________________

Step-by-step explanation:

Answer 2

Answer:

50,51,52 are the three consecutive number s