Question

find three consecutive numbers such that if they are divided by 10 , 17 and 26 respectively . The sum of their quotient will be 10.​

Answer 1

Step-by-step explanation:

let the 3 consecutive no.s be x-1,x,x+1

let quotients be a, b, c

=> a=(x-1)/10

b=x/17

c=x+1 /26

and a+b+c=10

(x-1) x (x+1)

=> ___+___+ ___ = 10

10 17 26

221(x-1)+130x+85(x+1)

_________________=10

2210

=>436x-136 = 22100

=>x=22236/436=51

so the no.s are 50, 51, 52