Question

Find three consecutive numbers such that if they are divided by 10,17,and 26 respectively , the sum of their quotients will be 10.

Answer 1

50, 51, 52

Explanation:

let the consecutive numbers = x/10 + x+1/17 + x+2/26 = 10

211x + (130×130) + (85x+170)/2210 = 10

436x+300=22100

436x =22100-300

x= 21800/436

x=50

x+1=51

x+2=52

Therefore, the 3 consecutive numbers are 50, 51 and 52

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Answer 2

First number = x = 50

Second number = x+1 = 51

Third number = x+2 = 52