Question

find three consecutive numbers such that if they are divided by 10,17 and 26 respectively the sum of their quotients will be 10 ​

Answer 1

Answer:

Let the consecutive numbers be x, x+1, and x+2

If they are divided by 10, 17 and 26 respectively,

Then,

⇒(x/10) + (x+1/17) + (x+2/26) =10

​ ⇒442x + (260)(x+1)+(170)(x+2)=442×100

⇒872x+600=442×100

⇒x=50

So, the consecutive numbers are 50, 51 and 52

Answer 2

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