find three consecutive numbers such that if they are divided by 10 17 26 respectively sum of their portion will be ten
Answers
Answered by
1
Step-by-step explanation:
jSolution
verified
Verified by Toppr
Let the consecutive numbers be x,x+1 and x+2
If they are divided by 10,17 and 26 respectively,
Then,
10
x
+
17
x+1
+
26
x+2
=10
⇒442x+(260)(x+1)+(170)(x+2)=442×100
⇒872x+600=442×100
⇒x=50
So, the consecutive numbers are 50,51 and 52
Answered by
1
Step-by-step explanation:
17 26 respectively sum of their portion will be ten
Similar questions