Question

find three consecutive numbers such that seven times the smallest number may be equal to three times the sum of the other two

Answer 1

Hope the answer helps you

Answer 2

Let three consecutive numbers be x, x + 1, x + 2.

Seven times the smallest term....means 7x

is equal to three times the sum of others two....means 3(x + 1 + x + 2)

So,

7x = 3(x + 1 + x + 2)

7x = 3(2x + 3)

7x = 6x + 9

7x - 6x = 9

x = 9

x + 1 = 9 + 1 = 10

x + 2 = 9 + 2 = 11


So three consecutive numbers are.... $\textbf{9, 10, 11}$