Question

Find three consecutive numbers such that seven times the smallest may be equal to three times the sum of the other two​

Answer 1

Answer:

9, 10 , 11

Step-by-step explanation:

Let the three consecutive numbers be x, x + 1, and x + 2 respectively.

According to the question ;

7x = 3 ( x + 1 + x + 2 )

⇒ 7x = 3 ( 2x + 3 )

⇒ 7x = 6x + 9

⇒ 7x - 6x = 9

⇒ x = 9

Therefore, the three consecutive numbers are ;

• x = 9
• x + 1 = 10
• x + 2 = 11

Hence, the numbers are 9, 10 and 11.

Answer 2

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