Find three consecutive numbers such that the sum of first and second is 15 more than the third number .
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Step-by-step explanation:
Let the first consecutive number = x,
Second consecutive number = x + 1
and Third consecutive number = x + 2
According to the condition,
x + x + 1 = 15 + x + 2
⇒ 2x + 1 = 17 +x
⇒ 2x -x = 17 – 1
⇒ x= 16
∴ The first consecutive number = 16
Answered by
0
Answer:
ITS 16, 17, 18
Step-by-step explanation:
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