Question

find three consecutive numbers such that the sum of the first and second is 15 more than third​

Answer 1

Answer:

Let the numbers be (x+1),(x+2) and (x+3)

Then a/q

x+1+x+2-15=x+3

2x-12=x+3

2x-x=3+12

x=15

Therefore the required number

=x+1=15+1=16

=x+2=15+2=17

=x+3=15+3=18

Answer 2

Solution :

Let , the three consecutive numbers are x , x + 1 and x + 2

By the given condition ,

$\sf \hookrightarrow first \: no. + second \: no. = third \: no. + 15 \\ \\ \sf \hookrightarrow</p><p>x + x + 1 = (x + 2) + 15 \\ \\ \sf \hookrightarrow</p><p>2x + 1 = x + 17 \\ \\ \sf \hookrightarrow </p><p>x = 16$

Thus , the required numbers are 16 , 17 and 18 respectively