Question

Find three consecutive numbers such that the sum of the first and third is 36.

Answer 1

Answer:

let the first no. be x

second consecutive no. be x+1

third consecutive no. be x+2

A/Q

x+x+2=36

2x=34

x=17

hence the first no. =17

second no.= 18

third no.=19

hope it helped you

please mark my answer as brainlist

Step-by-step explanation:

Answer 2

Answer:

First number = 17

Second number = 18

Third number = 19

Step-by-step explanation:

First number = x

Second number = x + 1

Third number = x + 2

Sum of first and third number = 36

x + x + 2 = 36

2x + 2 = 36

2x = 36 - 2

2x = 34

x = 34/2

x = 17

First number = x = 17

Second number = x + 1 = 18

Third number = x + 2 = 19

Check ⇒

First number = x = 17

Second number = x + 1 = 18

Third number = x + 2 = 19

Sum of first and third number = 36

17 + 19 = 36

36 = 36

L.H.S = R.H.S

Hence, verified.

The answer is correct.

                HOPE IT HELPS U!

             MARK AS BRAINLIEST!