find three consecutive numbers, such that the sum of the second and the third number exceeds the first by 28
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Answer:
25 , 26 , 27
Step-by-step explanation:
Let the numbers be -
x , x+1 and x+2
==: (x+1) + (x+2) - x = 28
==: 2x + 3 - x = 28
==: x = 25
Numbers = x = 25
= x + 1 = 26
= x + 2 = 27
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