find three consecutive numbers such that the sum of the second and the third number exceeds the first by 28
Answers
Answered by
16
Answer:
the three integers are,
x=25
x+1=26
x+2=27
Step-by-step explanation:
Let the three consecutive numbers be x, x+1, x+2.
According to the question,
sum of 2nd and 3rd term = First term + 28
x+1+x+2 = x + 28
2x+3 = x +28
2x - x = 28 - 3
x = 25
so the three integers are,
x=25
x+1=26
x+2=27
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Answered by
1
Answer:
27 is wrong answer this is my book questions in which our mam say there is 25 answer
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