Find three consecutive numbers such that the sum of the first and the third is 36.
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please tell the ans if you know ..
Answers
Answered by
5
Answer:
let the first number be x
second number be x+1
third number be x+1+1 = x+2
given,
x+x+2 = 36
2x = 36 - 2
2x = 34
x = 17
the three consecutive numbers are x = 17, x+1 =18,
x+2 = 19
Answered by
2
Answer:
3 consecutive number's are = 17 , 18 , 19
Step-by-step explanation:
let 3 consecutive number be (x - 1) , x, (x + 1)
sum of 1st and 3rd number = 36
i. e. (x - 1) + (x + 1) = 36
2x = 36
x = 18
so 3 consecutive numbers are :-
1st = (x-1) = (18 - 1) = 17
2nd = x = 18
3rd = (x + 1) = (18 + 1) = 19
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