Math, asked by aarya80, 11 months ago

find three consecutive numbers such that the sum of the second and the third number exceeds the first by 14

Answers

Answered by kumartanuj941
14

Answer:


Step-by-step explanation:

Let the first number be x

Second be x+1 and third be x+2


According to the question :

(X+1+X+2)-X=14

2X+3-X=14

X=14-3

X=11


THEREFORE THE NUMBERS ARE 11,12 AND 13

Answered by syonbopanna
4

Answer:

Step-by-step explanation:

Let the first number be x

Second be x+1 and third be x+2

According to the question :

(X+1+X+2)-X=14

2X+3-X=14

X=14-3

X=11

THEREFORE THE NUMBERS ARE 11,12 AND 13

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