Question

find three consecutive numbers such that three-times the middle number is greater than the sum of the other two by 11.

Answer 1

let the three no. be x,x+1,x+2
according to the question
3(x+1)=x+x+2+11
3x+3=2x+13
x=10
the three no. are 10,11,12

Answer 2

Let three consecutive number be a, a+d, a+2d

3(a+d) = a+a+2d+11
3a+3d = 2a+2d+11
3a-2a+3d-2d=11
a+d=11

The middle number is 11
Therefore the 3 consecutive nos are 10,11,12