Question

find three consecutive numbers such that twice the greatest added to three times the least amount to 34​

Answer 1

EXPLANATION

Let n = the least of the 3 consecutive numbers.

n+1 = the middle number

n+2 = the greatest number

Now build an equation:

Twice the greatest: 2•(n+2)

Added to: +

Three times the least: 3•n

Amount to 34: = 34

Put it all together and solve for n.

2(n+2) + 3n = 34

2n + 4 + 3n = 34

5n = 30

n = 6

n is the least of the 3 consecutive numbers, so…

The 3 consecutive numbers are 6, 7, and 8.

mark me as brainliest