find three consecutive numbers such that when the third number is subtracted from the sum of the first two numbers, the difference is 10
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let first no be =x
therefore second no = x+1
and third no = x+1+1
= x+2
A/Q:- first no. + second no - third no.=10
x+x+1-x-2=10
x-1=10
x=11
second no. = x +1
= 11+1=12
third no. = x+2
=11+2=13
therefore second no = x+1
and third no = x+1+1
= x+2
A/Q:- first no. + second no - third no.=10
x+x+1-x-2=10
x-1=10
x=11
second no. = x +1
= 11+1=12
third no. = x+2
=11+2=13
ayushkumar17:
hope it help u
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