Question

find three consecutive numbers who sum is 342

Answer 1

Let the three consecutive numbers be

x, x+1, x+2

So their sum is 342

342= x+(x+1)+(x+2)

342=3x+3

342-3=3x

339=3x

x=113

So the consecutive numbers are

113,. 114, 115

Hope it helps

Answer 2

Let the 1st no. be x.

2nd no. be x +1.

3rd no. be x +2.

Atq. x + x +1 + x + 2 =342.

or 3x + 3. = 342

or 3x = 342 -3

or 3x = 339

or. x. =339/3

Therefore x = 113.

So.

1st no. = x = 113.

2nd no. = x +1 = 113 +1 =114.

3rd no. = x +2 =113 + 2 =115.