Math, asked by bhartichidguppikar73, 6 months ago

Find three consecutive numbers whose sum a
36.​

Answers

Answered by Shwetasharma99736
0

Answer:

11, 12 and 13

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Answered by faisalfiroz02
3

Answer:

The numbers are 11,12 and 13.

Step-by-step explanation:

Let the 3 consecutive numbers be X,X+1 and X+2

Given that, X+X+1+X+2 = 36

3X+3 = 36

3X = 36-3

3X = 33

X = 33/3

X = 11

Therefore, The numbers are 11,12 and 13.

Check: 11+12+13 = 36.

Hope it helps you.

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