Find three consecutive numbers whose sum a
36.
Answers
Answered by
0
Answer:
11, 12 and 13
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Answered by
3
Answer:
The numbers are 11,12 and 13.
Step-by-step explanation:
Let the 3 consecutive numbers be X,X+1 and X+2
Given that, X+X+1+X+2 = 36
3X+3 = 36
3X = 36-3
3X = 33
X = 33/3
X = 11
Therefore, The numbers are 11,12 and 13.
Check: 11+12+13 = 36.
Hope it helps you.
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