Question

Find three consecutive numbers whose sum is 108.​

Answer 1

Answer:

Three consecutive evenintegers can be represented by x, x+2, x+4. The sum is 3x+6, which is equal to 108. Thus, 3x+6=108.

Answer 2

Step-by-step explanation:

Consider the three consecutive numbers,

x,x+1 and x+2

Now ,according to question,

x+(x+1)+(x+2)=108

3x+3=108

3x=105

x=35

Required three numbers are,

x=35,x+1=36 and x+2=37

Hence, this is the answer.