find three consecutive numbers whose sum is 108
Answers
Answered by
11
x + x +1 +x+2 =108
3x =108-3=105
x =35
so no are 35 ,36,37
3x =108-3=105
x =35
so no are 35 ,36,37
Answered by
36
Let take that consecutive numbers as
x , x+1 , x+2
x+(x+1)+(x+2) = 108
3x + 3 = 108
3x = 108-3
3x = 105
x = 105/3
x = 35
numbers are
35 , 36 , 37
x , x+1 , x+2
x+(x+1)+(x+2) = 108
3x + 3 = 108
3x = 108-3
3x = 105
x = 105/3
x = 35
numbers are
35 , 36 , 37
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