Question

Find three consecutive numbers whose
sum is 126.

Answer 1

Step-by-step explanation:

Let's take the variable as x

Then according to the question,

x+x+1+x+2=126

=> 3x + 3 =126

=>3x=126-3=123

=> x = 123/3

=> x= 41

So the numbers are : 41, 41+1=42, 41+2 = 43

Answers: 41,42,43

Answer 2

$\huge{\boxed{\huge{\red\star\mathfrak\purple{\large{\underline{\underline{ Answer!}}}}}}}$

Let the common ratio be x

1st number= x

2nd number= x+1

3rd number= x+2

Sum of the consecutive numbers= 126

Now, According to the question

x+(x+1)+(x+2)= 126

⟹3x+3= 126

⟹3x= 126-3

⟹3x= 123

$\huge \boxed{ \mathfrak \red{\implies \: x = 41}}$

1st number= x= 41

2nd number= x+1= 41+1= 42

3rd number= x+2= 41+2= 43