Find three consecutive numbers whose sum is 147
Answers
Answered by
2
Let the first number be x
Therefore
X+(X+1)+(X+2)=147
3x=144
X=48
X+1 =49
X+2=50
Therefore
X+(X+1)+(X+2)=147
3x=144
X=48
X+1 =49
X+2=50
Answered by
1
Let a,a+1,a+2 be the three consecutive numbers
Then,
a+a+1+a+2=147
3a+3=147
3a=147-3
3a=144
a=144/3
a=48
The three numbers are 48, 48+1=49, 48+2=50
Then,
a+a+1+a+2=147
3a+3=147
3a=147-3
3a=144
a=144/3
a=48
The three numbers are 48, 48+1=49, 48+2=50
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