Find three consecutive numbers whose
sum is 303.
Answers
Answered by
4
Answer:
Three consecutive numbers whose sum is 303:
100, 101, 102.
Answered by
9
Answer:
let the no.s be x, x+1 & x+2
so x+x+1+x+2= 303
-> 3x+3= 303
-> 3x = 303-3
-> 3x = 300
-> x = 300/3
-> x = 100
x is 100.
x+1= 100+1= 101
x+2= 100+2= 102
therefore, the three consecutive numbers that form 303 are 100, 101 & 102.
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