find three consecutive numbers whose sum is 48 ?
Answers
Answered by
46
Let the first number be a
Second number = a +1
Third number = a +2
According to question
a + a +1 + a + 2 = 48
=> 3a + 3 = 48
=> 3a = 45
=> a = 15
First number = 15
Second number = 16
Third number = 17
Second number = a +1
Third number = a +2
According to question
a + a +1 + a + 2 = 48
=> 3a + 3 = 48
=> 3a = 45
=> a = 15
First number = 15
Second number = 16
Third number = 17
Answered by
28
Let first no. Is x
so 2 no. Is (x+1) and 3 no. Is (x+2)
So sum is 48
x+x+1+x+2=48
3x + 3 =48
3x=45
x=15
So three consecutive no. Are 15 , 16, 17
so 2 no. Is (x+1) and 3 no. Is (x+2)
So sum is 48
x+x+1+x+2=48
3x + 3 =48
3x=45
x=15
So three consecutive no. Are 15 , 16, 17
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