Find three consecutive numbers whose sum is 48 and 342
Answers
Answered by
15
x+x+1+x+2=48
3x +3=48
3x=48-3
3x=45
x=45/3
x=15
3x +3=48
3x=48-3
3x=45
x=45/3
x=15
Answered by
7
Answer:
15,16,17
Step-by-step explanation:
Let the first no. be = x
second no. = x+1
third no . = x+2
= x+x+1+x+2=48
= 3x + 3=48
= 3x=48-3
= 3x=45
= x=45÷3
= 15
First no . = 15
Second no. = 15 +1 = 16
Third no. = 15 + 2 = 17
#Answerwithquality #BAL
Similar questions