find three consecutive numbers whose sum is 63?
Answers
Answered by
3
let the numbers be
x-1 , x ,x+1
according to question
(x-1)+(x)+(x+1)=63
3x=63
X=63/3=21
the three consecutive numbers whose sum is 63 are
20,21,22
Answered by
2
Answer : 20,21,22.
Step-by-step explanation:
Solution :
Let us take the numbers to be added as -
X, X+1 , X+2,
.Now, X+ X+1 +X+2 = 63,
.Therefore, 3X + 3 = 63,
.3X = 63 - 3 = 60,
.therefore, X = 60/3 = 20.
.So the numbers are :
- X = 20,
- X+1 = 21
- X+2 = 22
- Hope it helps,
- Please mark my answer brainliest if it helped.
Similar questions