Question

Find three consecutive numbers whose sum is 72​

Answer 1

ǫᴜᴇsᴛɪᴏɴ ;

• Find three consecutive numbers whose sum is 72.

ᴀɴsᴡᴇʀ ;

• 23,24,25

ᴇxᴘʟᴀɴᴀᴛɪᴏɴ :

Let n = the first of three consecutive numbers.

Let n + 1 = the second consecutive number, and ...

Let n + 2 = the third consecutive number.

Since we're given that: "the sum of three consecutive numbers is 72," then we can now translate this statement mathematically into the following equation to be solved for the unknown number n:

n + (n + 1) + (n + 2) = 72

n + n + 1 + n + 2 = 72

Collecting like-terms on the left, we get:

3n + 3 = 72

3n + 3 - 3 = 72 - 3

3n + 0 = 69

3n = 69

(3n)/3 = 69/3

(3/3)n = 69/3

(1)n = 23

n = 23

Therefore, ,...

n + 1 = 23 + 1 = 24 and

n + 2 = 23 + 2 = 25

CHECK:

n + (n + 1) + (n + 2) = 72

23 + (24) + (25) = 72

23 + 24 + 25 = 72

72 = 72

Therefore, the three consecutive numbers whose sum is 72 are 23, 24, and 25, and 23 is obviously the smallest.

Answer 2

$\huge \underline \mathfrak{answer}$

The three consecutive numbers are x,x+1,x+2

So,

=X + X + 1 + X + 2=72

=3 X + 3 = 72

=3X=72-3

=X=69/3

=X=23

FINAL ANSWER

X=23

X + 1=24

X + 2=25