find three consecutive numbers whose sum is 81
anuj:
take three consecutive numbers as (x-1),x,(x+1) ,,,,,,,,,on adding u will get 3x=81 => x=27 => (x-1)=27-1= 26 => x+1=27+1=28
So, What's given in answers??
all i mean is instead of taking consecutive numbers as x,x+1,x+2 ,,,,,,,,,its better taking x-1,x,x+1
Ok, same
Thanks
Answers
Answered by
210
Let X, X+1 and X+2 be the three consecutive numbers,
Therefore,
X+(x +1) +(x + 2) =81
3X+3 =81
3X=81 -3
3 X = 78
X= 78 ÷3
X= 26
1st no= 26
2nd no = × +1 = 26 +1 = 27
3rd no = × + 2 = 26 +2 =28
Therefore,
X+(x +1) +(x + 2) =81
3X+3 =81
3X=81 -3
3 X = 78
X= 78 ÷3
X= 26
1st no= 26
2nd no = × +1 = 26 +1 = 27
3rd no = × + 2 = 26 +2 =28
true answer
26+27+28 =81 proof
nice answer
(:BRAINLY BENEFACTOR:)
Answered by
83
Heya.
Let the first digit be y.
The second number will be y +1.
The third number = y+2.
It is given that their sum is 81.
So, y + (y+1) + (y+2) = 81
3 y + 3 = 81
3y = 78
y = 26.
Hence,, y = 26
next digit = 27
Third digit = 28.
Let us verify,
26 + 27 + 28 = 81.
Hence, above answer is correct....
Hope it helps ..
Let the first digit be y.
The second number will be y +1.
The third number = y+2.
It is given that their sum is 81.
So, y + (y+1) + (y+2) = 81
3 y + 3 = 81
3y = 78
y = 26.
Hence,, y = 26
next digit = 27
Third digit = 28.
Let us verify,
26 + 27 + 28 = 81.
Hence, above answer is correct....
Hope it helps ..
answrd well
:)
-:)
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