Question

find three consecutive numbers whose sum is 81

Answer 1

Let ,three consecutive numbers be x , (x+1) , (x+2).

ATQ,

x+x+1+x+2=81

3x+3=81

3x=81-3

3x=78

x=78/3

x=26

Hence, three consecutive numbers whose sum is 81 is 26 , 27 , 28.

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Answer 2

Solution ●●●●
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$Let \: \: the \: \: three \: \: consecutive \: \: numbers \\ be \: \: y, \: \: (y + 1) \: \:and \: \: (y + 2)$

$A.T.Q.$

$y + y + 1 + y + 2 = 81$

$= > 3y + 3 = 81$

$= > 3y = 81 - 3$

$= > 3y = 78$

$= > y = \frac{78}{3 } \\ \\ = > y = 26$

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Required numbers :
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y = 26

y + 1 = 26 + 1 = 27

y + 2 = 26 + 2 = 28
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