Find three consecutive numbers whose sum is 81?
Answers
Answered by
55
let 3 number be (X),(x+2),(x+4)
so x+x+2+x+4 = 81
3x + 6 =81
3x = 81-6
3x = 75
x= 75÷3
x = 25
x+2 = 25 + 2
= 27
x+4 = 25 +4
= 29
so x+x+2+x+4 = 81
3x + 6 =81
3x = 81-6
3x = 75
x= 75÷3
x = 25
x+2 = 25 + 2
= 27
x+4 = 25 +4
= 29
singhisking3337:
oh....... sorry i answered wrong
sorry
is it wrong ?
You have to solve like this...
Let n, n+1, and n+2 are the three consecutive numbers. Therefore, n+n+1+n+2 = 81. 3n+3 = 81. 3n = 78. n = 26. Therefore, the three consecutive numbers are 26, 26+1 = 17, 26+2 = 29.
Answered by
18
Let "x" will be an unknown middle number.
Then the three numbers are (x-1), x and (x+1).
You are given that
(x-1) + x + (x+1) = 81, or, which is the same,
3x = 81.
Hence, x = 81%2F3 = 27.
So, your numbers are 26, 27 and 28.
hope it's helps ^_^
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