find three consecutive numbers whose sum is687
Answers
Answer:
Here we will use algebra to find three consecutive integers whose sum is 687.
We assign X to the first integer. Since they are consecutive, it means that the 2nd number will be X+1 and the third number will be X+2 and they should all add up to 687. Therefore, you can write the equation as follows:
X + X + 1 + X + 2 = 687
To solve for X, you first add the integers together and the X variables together. Then you subtract 3 from each side, followed by dividing by 3 on each side. Here is the work to show our math:
X + X + 1 + X + 2 = 687
3X + 3 = 687
3X + 3 - 3 = 687 - 3
3X = 684
3X/3 = 684/3
X = 228
Which means that the first number is 228, the second number is 228+1 and third number is 228+2. Therefore, three consecutive integers that add up to 687 are:
228
229
230
Since, 228 + 229 + 230 = 687, it confirms that the answer above is correct.
Answer:
THE THREE CONSECUTIVE NUMBERS WHOSE SUM IS 687 ARE 229 ; 230 ; 231
Step-by-step explanation:
let the three consecutive number be
x ,x+1 ,x+2
According to the question...
x+(x+1)+(x+2) =687
x+x+1+x+2 = 687
3x + 3=687
3x=687-3
3x=684
x=687/3
x=228
x=228
x+1=228+1=239
x+2= 228+2=230