Find three consecutive numbers whose sum shall equal 45
Answers
Answered by
4
Answer:
14 , 15 , 16
Step-by-step explanation:
Let the numbers be x-1 , x , x+1 .
Then by the given condition ,
(x-1) + x + (x+1) = 45
3x = 45
x = 15
So , the numbers are (15-1) , 15 , (15+1) ; i.e. 14 , 15 , 16 .
Answered by
3
The three numbers are 14,15and16.
Let three consecutive numbers be x,x+1andx+2.
Then, According to question,
x+x+1x+2=45
3x+3=45
3x=45-3
3x=42
x=42/3
x=14
Three numbers are
x=14
x+1=14+1=15
x+2=14+2=16
the three consecutive numbers whose sum shall equal 45 are 14,15and16.
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