Question

Find three consecutive odd integer such of the first number,two less than the second number and three more than the third number is 70.

Plz answer in explanation

Answer 1

Answer:

the no.s are 21,23 and 25

Step-by-step explanation:

let the no.s be

x,x+2,x+4

a/q

x+(x+2-2)+(x+4+3)=70

x+x+x+7=70

3x+7=70

3x=63

x=21