Question

find three consecutive odd integers such that the sum of twice the first, the second and three times the third is 152​

Answer 1

ANSWER:

• The three consecutive odd integers are 23, 25, 27.

GIVEN:

• Sum of twice the first, the second and three times the third is 152.

TO FIND:

• The three consecutive odd integers.

EXPLANATION:

Let us take a number 2n.

n may be any natural number.

2n is absolutely even. As 2 times any number is always even.

•°• 2n + 1 will absolutely odd.

Let the cosecutive odd numbers be 2n + 1, 2n + 3, 2n + 5.

=> 2(2n + 1) + 2n + 3 + 3(2n + 5) = 152

=> 4n + 2 + 2n + 3 + 6n + 15 = 152

=> 12n + 20 = 152

=> 12n = 132

=> n = 11

First number = 2n + 1

=> Substitute n = 11

=> First number = 2(11) + 1

=> First number = 22 + 1

=> First number = 23

Second number = 2n + 3

=> Substitute n = 11

=> Second number = 2(11) + 3

=> Second number = 22 + 3

=> Second number = 25

Third number = 2n + 5

=> Substitute n = 11

=> Third number = 2(11) + 5

=>Third number = 22 + 5

=> Third number = 27

Hence the three consecutive odd integers 23, 25, 27.