Find three consecutive odd integers such that the sum of the largest and twice the smallest is 25. If x represents the smallest integer, then which equation could be used to solve the problem?
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Answer:
3x+4 =25
Step-by-step explanation:
since it is given that the smallest odd integer is x, the next two odd numbers are x+2 and x+4. Hence x+4+2(x)=25.
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