Question

Find three consecutive odd integers such that the sum of the largest and twice the smallest is 25.

Answer 1

Step-by-step explanation:

Let three consecutive odd integer's be x , x + 2 and x + 4.

Therefore,

Smallest number = x

And,

Largest number = x + 4.

According to the question,

Largest number + 2 ( smallest number ) = 25

=> x +4 + 2 ( x ) = 25

=> x + 4 + 2x = 25

=> 3x + 4 = 25

=> 3x = 25 - 4

=> 3x = 21.

=> X = 21/3 = 7.

Therefore,

First number = X = 7

Second number = x + 2 = 7+2 = 9

And , Third number = x + 4 = 7 + 4 = 11.

Hope it will help you :)

=> 3x = 17