Question

Find three consecutive odd integers such that the sum of the first and the third is 70.

Answer 1

Answer:

33

Step-by-step explanation:

let the consecutive no. be x, x+2, x+4

x+x+4=70

2x+4=70

2x=66

x=66/2

x=33

Answer 2

Step-by-step explanation:

Let's say that the first odd integer is x.The second consecutive odd integer would have to be x+2 .(It would not be x+1 because that would result in an even integer. The sum of any two odd numbers is even.) The third consecutive odd integer would be (x+2)+2 , or x+4 .The sum of the first, twice the second, and three times the third can be written as

x+2(x+2)+3(x+4)

This equals 70 . We can now distribute and solve for x .

x+2

(x+2)+3(x+4)=70

x+2x+4+3x+12=70

→ distribute

6x+16=70

→ gather like terms6x=54

→ subtract 16 from both sides

x=9

→ divide both sides by 6

Thus, the three consecutive odd integers are 9,11, and 13 .

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