Question

Find three consecutive odd integers such that the sum of the first number, two less than the second number and three more than third number is 70.
(GIVE THE ANSWER IN FULL PROCEDURE)

Answer 1

Answer:

The third consecutive odd integer would be (x+2)+2 , or x+4 . This equals 70 . We can now distribute and solve for x . Thus, the three consecutive odd integers are 9,11, and 13