Find three consecutive odd integers such that the sum of the first number, two less than the second Enumber and three more than the third number is 70.
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Let the 3 consecutive odd integer be ;x,x+2,x+4
x+2(x+2)+3(x+4)=70
x+2x+4+3x+12=70
6x+16=70
6x=54
x=9
∴3 no : are : 9,11,13
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