Question

Find three consecutive odd integers such that the sum of the first and the third integers is two more than twice the second. Show steps please.

Answer 1

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Hello,

Let's first assign some terms to the problem, fair enough?

x = the first consecutive odd integer

x + 2 = the second consecutive odd integer

x + 4 = the third consecutive odd integer

2(x) + 3(x +2) = 2(x + 4) + 79 2x + 3x +6 = 2x + 8 + 79 <----combine like terms5x + 6 = 2x + 87 <--------------solve for x 3x +6 = 87 3x = 81 x = 27 Now, substitute the value for x in your equation. 2(27) + 3(27 + 2) = 2(27 + 4) + 79 54 + 81 + 6 = 54 + 8 + 79 141 = 141