Find three consecutive odd integers such that the sum of the first number, two less than the second number and three more than the third number is 70.
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Step-by-step explanation:
hlo mate here's your answer
Let the3consecutive odd integer be
;x,x+
2,x+
4
x+ 2(x+ 2)+ 3(x+ 4)= 70
x+ 2x+ 4+ 3x+ 12= 70
6x+ 16= 70
6x= 54
x= 9
∴ 3
9,11,13
i hope its help you mark as brainlist plz
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above is
your answer
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