Find three consecutive odd integers such that the sum of the first number, two less than the second number and three more than the third number is 70. Give correct answer
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Let the 3 consecutive odd integers be x,x+2,x+4
x+2(x+2)+3(x+4)=70
x+2x+4+3x+12=70
6x+16=70
6x=54
x=9
∴the 3 numbers are 9, 11 and 13
x+2(x+2)+3(x+4)=70
x+2x+4+3x+12=70
6x+16=70
6x=54
x=9
∴the 3 numbers are 9, 11 and 13
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